Use the information below to answer this question
c(s) + o2(g) → co2(g) ∆h = −393.5 kj mol−1
h2(g) + o2(g) → h2o(l) ∆h = −285.8 kj mol−1
3c(s) + 4h2(g) → c3h8(g) ∆h = −104.0 kj mol−1
4c(s) + 5h2(g) → c4h10(g) ∆h = −125.2 kj mol−1
the value in kj mol−1
for the enthalpy of combustion of propane is

First, construct a balance equation for the combustion of propane. Then the 3rd equation given in the question is the formation of propane. So 1 mol of propane is formed by -104 kJ mol-1. Then, the 1st equation given in question is the formation of CO2. 3 mol of CO2 is formed so 3(-393.5). 2nd equation shows that 1 mol of H2O is formed but based on balanced equation that I constructed, 4 mol of H2O is formed so 4(-285.5). The arrows I drew was for the mathematics equation. Going to same direction of the product of combustion of propane FROM the reactant is -104 and x so I put this on the left side. Then, the remaining one is on the right side.

Answer:

a. energy is absorbed in the reaction.

explanation:

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.

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