If a person burns 2171 cal each day, how much energy (kj) does she burn in 2 days?

She will burn 18.17 KJ of energy in 2 days.

Energy can be measured in both joules and calories. The following units of energy are converted as follows:

1 calorie = 4.184 Joules

2171 calories = (2171 × 4.184) joules

= 9083.464 Joules

Since 1 kilojoules = 1000 joules

9083.464 Joules = (9083.464/1000) KJ

= 9.083 KJ

This means that the person burns 9.083 KJ of energy per day.

Hence, in 2days, the person will burn;

2 × 9.083 KJ

= 18.17 KJ of energy.

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question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

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(jacemorris04)