What is the concentration of 10.00 ml of hbr if it takes 5ml of a 0.253m lioh solution to neutralize it?

The chemical reaction would be:

HBr + LiOH = LiBr + H2O

We are given the concentration of the other reactant. We use these given values and the reaction to relate to moles of HBr needed. We do as follows:

0.253 mol / L ( .005 L) ( 1 mol HBr / 1 mol LiOH ) = 0.0013 mol HBr

Molarity = 0.0013 / 0.01 = 0.13 M

Sorry i dont understand the question can you rephase it?