Chemistry, 20.10.2019 19:00 amy1983

Aparticular reaction, a → products, has a rate that slows down as the reaction proceeds. the half-life of the reaction is found to depend on the initial concentration of
a. determine whether each statement is likely to be true or false for this reaction.

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Generally, the rate of a reaction will decrease with increasing temperature, although there are some exceptions in the case of non-elementary reactions. However it is more likely that the first statement is false.
Half-life is a measure of the time taken for a to reach 1/2 of its initial concentration, and is generally completely independent of reagent concentration within a first order reaction, which is likely what this reaction is, therefore statement 2 is also likely false.
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Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

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Aparticular reaction, a → products, has a rate that slows down as the reaction proceeds. the half-li...