Mixing 25.0 ml of 1.2 m hclo4 and 25.0 ml of 1.1 m naoh were mixed. the temperature of the initial solution was 22.4 o
c. assuming a heat of neutralization of 55.8 kj/mol, what would the final temperature be if the specific heat for this solution is 4.032 j/g o ?

You know how the first one if filled up like the objects do the same but with the other categories

The correct answer is c. orbital shape. "the angular momentum quantum number l describes the shape of an orbital. it corresponds to each orbital type, i.e. (0,1,2,−1)=(s,p,d,f,g,"

Ch4 and ph3 are both covalent since they are composed both of non-metals.    ch4 is non- polar because of  london forces and has a geometry of tetrahedral  ph3 , on the other hand, is umbrella shaped polar and has dipole-dipole intermolecular force (imf) . since ph3 is polar, it has a stronger imf