In the equilibrium system below, which of the following changes would cause the equilibrium position to shift to the right?

2so3(g) two arrows stacked on top of each other. the top arrow points to the right. the bottom arrow points to the left. 2so2(g) + o2(g) deltah = +197 kj/mol

a) decrease the temperature
b) increase the volume
c) add more o2 gas
d) add a catalyst

B. Increase the volume (in other words, decrease the pressure).
A is wrong because as temperature decreases, the reaction will shift to the left as the system is endothermic (positive delta H).
C. is wrong because as O2 gas is added, the reaction will shift to the left in order to relieve the stress on the system.
D. is wrong because a catalyst will increase the rate of the reaction by decreasing the activation energy. It doesn't affect equilibrium.
B is correct because the left side has two moles of gas while the right side has three moles of gas. Thus, when pressure is decreased (volume is increased--they are inversely related), the system will shift in the direction with more moles of gas. 

Answerδh > 0explanationc₆h₆  (s)  → c₆h₆ (l)if you are changing it from a solid to a liquid, you are pretty much melting the solid. this requires heat energy. therefore, the reaction is endothermic (takes in energy); the system enthalpy increases as the reaction proceeds: δh > 0.

Answer it is also known as the completion state is untrue of the activation complex;