What is the balanced net ionic equation for the reaction in acidic solution of fe2+ and kmno4? fe2+ + mno4 + 8h+ 5fe3+ + mn2+ +3h2o 5fe2+ + mno4- 5fe3+ + mn2+ 5fe2+ + mno4 -+ 8h+ 5fe3+ +mn2+ +4h2o 3fe2+ + mno4 3fe3+ + mn2+ + h2o

:  What is the balanced net ionic equation for the reaction in acidic solution of FeCl2 and KMnO4 (Fe2+ becomes Fe3+ and MnO4 becomes Mn2+). (1 point) 

your answer is: 
5Fe2+ + MnO4– + 8H+ 5Fe3+ + Mn2+ + 4H2O 

... 

What happens to the color of the FeCl2 when the equivalence point is reached? (1 point) 

that's a hard one to answer... 
Fe+2 green color converts into Fe+3 which is yellowish at the equivalence point... 

but at the end point, an excess drop of KMnO4 is added, & its pink color mixes with Fe+3 's yellow to give an orangish color 

The color turns purple. is way too much KMnO4 added 
The color turns green., not at the equiv point yet, still alot of Fe+2 
The color turns red. ( i would rather say reddish -orange) 

now if you added phosphoric acid to eleiminate the yellow color of Fe+3, ... 
then your equivalence point should be colorless, and your end point with 1 excess drop of KMnO4 should be pink 

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.