The dissociation of a weak electrolyte is suppressed when a strong electrolyte with a common ion is added to the weak electrolyte solution. a strong salt is dissolved with the weak electrolyte solution. a strong electrolyte with a different ion than the weak electrolyte is added. the strong electrolyte solidifies in the presence of the weak electrolyte.

when a strong electrolyte with a common ion is added to the weak electrolyte solution.

The dissociation of a weak electrolyte is suppressed when a strong electrolyte with a common ion is added to the weak electrolyte solution.

when a strong electrolyte with a common ion is added to the weak electrolyte solution.

The dissociation of a weak electrolyte is suppressed when a strong electrolyte with a common ion is added to the weak electrolyte solution.

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

b) mutualism

hope this : )