Amixture of 10.0 g of ne and 10.0 g ar have a total pressure of 1.6 atm. what is the partial pressure of ne?

1.1atm

Explanation: A mixture of 10.0 g of Ne and 10.0 g of Ar has a total pressure of 1.6 atm. What is the partial pressure of Ne?

a. 1.1 atm

b. 0.8 atm

c. 0.54 atm

d. 0.40 atm

e. 1.3 atm

In any mixture of gases, the partial pressure of the individual components of the mixture is the pressure which that component would normally occupy if it were present alone under the same circumstance. To calculate the partial pressure (p) of Ne in a mixture of Ne and Ar, the partial pressure of a gas in a mixture is given by mole fraction (X) of the gas multiplied by the total pressure (P) of the mixture.

n Ne = 10g /20.18 g/gmol = 0.4955 moles

n Ar = 10g /39.95 g/gmol = 0.2503 moles

Total number of moles = 0.4955 + 0.2503 = 0.7458 moles

X Ne = 0.4955 / 0.7458 = 0.6644

p Ne = (X Ne)(P)

= 0.6644 x 1.6 = 1.063 atm

Which is approximately 1.1atm as answer

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.