One mole of propane (44 grams) reacts with 5 moles of oxygen to produce 2220 kj of heat. how many grams of propane would produce 6660 kj of heat? a.220 g b. 132 g c. 4440 g d.49 g

The correct answer is option B.

132 grams of propane would produce 6660 kJ of heat.

Explanation:

Explanation:

According to chemical reaction, combustion of 1 mole of propane gives 2,220  kilo Joules of heat , then 6,660 Kilo joules of heat will be obtained from :

Mass of 3.000 moles of propane :

3.000 mol × 44 g/mol = 132 g

132 grams of propane would produce 6660 kJ of heat.

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