Asolution of h2so4(aq) with a molal concentration of 3.58 m has a density of 1.200 g/ml. what is the molar concentration of this solution?

Best A molality of 2.55 indicates 2.55 mol of solute per 1 kg of solvent. Assume exactly 1 kg of water, and thus 2.55 mol of H2SO4.

The molar mass of H2SO4 is 2(1.0079 g/mol) (32.066 g/mol) 4(15.999 g/mol)=98.0778 g/mol.

2.55 mol H2SO4 x (98.0778g / 1 mol) = 2.50 x 10^2 g H2SO4

The mass of the water is 1 kg = 1000 g. the total mass of solution is

(2.50 x 10^2 g H2SO4) + (1000 g H2O) = 1.250 x 10^3 g solution

Use the mass and density of the solution to find the volume

1.250 x 10^3 g solution x (1 mL / 1.151g ) x (1 L / 1000mL) = 1.086 L solution

Finally, molarity is the number of moles of solute per liter of solution

(2.55 mol H2SO4 / 1.086 L solution ) = 2.35 M
Source(s):
Sapling Learning.com (the website we do our chemistry homework and that was the response given to me. good luck. hope you got it on time...

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