How many grams of koh are needed to prepare 250. millimeters of a 2.00 solution of koh

Use the concentration given to get the answer and the molar mass of the substance. 

250 ml (1 Liter/ 1000 ml) (2.00 mol KOH/ 1 liter) ( 56.1 grams/ 1 mole KOH)= 28.1 grams

250 ml (1 Liter/ 1000 ml) (2.00 mol KOH/ 1 liter) ( 56.1 grams/ 1 mole KOH)= 28.1 grams

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

Hcn is the correct answer leave a good rate and .