How many molecules of oxygen are produced by the decomposition of 6.54 g of potassium chlorate (kclo3)?

4.819 x 10^22

Explanation:

6.54 * 3/2 * 1/122.5492 * 6.02*10^23/1 = 4.818978826*10^22 (ROUND IT)

=4.819 x 10^22 molecules O2

FORMULA

Given gram(6.54) * Mole of Oxygen in chemical equation (3)/ Mole of potassium chlorate in chemical equation (2) *  1 mol of potassium chlorate/Molar mass of potassium chlorate (122.5492)* 6.02*10^23/ 1 mole of oxygen

= molecules of oxygen

Advice:

the formula is same as mass mole calculation  but you just need to multiply 6.02*10^23/ 1 mole of wanted (oxygen) in the end.

answer seismograph;