In the reaction mgcl2 + 2koh mg(oh)2 + 2kcl, if 6 moles mgcl2 are added to 6 moles koh, which is the limiting reagent?

Answer is: potassium hydroxide (KOH).

Balanced chemical reaction: MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl.

n(MgCl₂) = 6 mol; amount of magnesium chloride.

n(KOH) = 6 mol; amount of potassium hydroxide.

From balanced chemical reaction: n(MgCl₂) : n(KOH) = 1 : 2.

6 mol : n(KOH) = 1 : 2.

n(KOH) = 6 mol · 2.

n(KOH) = 12 mol; potassium hydroxide is limiting reagent, because we need 12 moles of it for chemical reaction and there is only 6 moles.

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.