Pure acetic acid has a density of 1.049 g/ml calculate the molarity of pure acetic acid

Molarity = mol/L

density= grams/ mL

this is a conversion problem where we have to change the numerator from grams to moles, and the denominator from ml to L.

First, we need our conversion factors

1 liters= 1000 mililters

to convert the mass to moles, we need the molar mass of the compound acetic acid (CH3COOH)

molar mass of CH3COOH is 60.05 g/mol, which can be calculated by going to the periodic table and add the mass of the each atom in the compound formula. 

1.049 g/ ml (1 mol/ 60.05 grams)= 0.0175 mol/ ml

0.0175 mol/ ml (1000 ml/ 1 liters)= 17.5 mol/ L or 17.5 M

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

The air is going to come out because of the low pressure.