Aswimming-pool worker wants the pool's ph to be 7.2. she comes by to test the water and finds that the ph is 8.2. what should she do to correct this situation?

The pH of a solution is a measure of the acidity of a solution and is logarithmically related to the hydrogen ion concentration. It is expressed as:

pH = -log [H+]

We use this to determine the amount of H+ needed to adjust the pH to the desired value.

pH1 = 7.2 = -log [H+]
[H+] = 6.31x10^-8

pH2 = 8.2 = -log [H+]
[H+] = 6.31x10^-9

[H+] to be added =  6.31x10^-8 - 6.31x10^-9 = 5.68x10^-8 M

She should add an acidic solution with concentration 5.68x10^-8 M. Hope this helps.