For the reaction given below at 700°c, kc = 0.534. h2(g + co2(g h2o(g + co(g calculate the number of moles of h2 that are present at equilibrium if a mixture of 0.229 moles of co and 0.229 moles of h2o is heated to 700°c in a 11.0-l container.

Answer : The concentration of at equilibrium is 0.012 M

Solution :

First we have to calculate the concentration of and .

Concentration of =

Concentration of =

The given equilibrium reaction is,

Initially conc.     0.0208   0.0208          0        0

At equilibrium.  (0.0208-x) (0.0208-x)  x       x

The expression of will be,

For given reaction the value of will be, (for reverse reaction).

By solving the term x, we get

Thus, the concentration of at equilibrium = x = 0.012 M

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong