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a force of 2,500 pounds drags a truck 30 feet in 1/2 minute.

how much work is accomplished?

how much power was required?

work = 75,000 ft-lbs, power = 32, 5000 ft-lbs/sec
work = 7,500 ft-lbs, power = 250 ft-lbs/sec
work= 75,000 ft-lbs, power = 2,500 ft-lbs/sec

Answer asap need by wednesday morning explain how a buffer works, using an ethanoic acid/sodium ethanoate system including how the system resists changes in ph upon addition of a small amount of base and upon addition of a small amount of acid respectively. include the following calculations in your i. calculate the ph of a solution made by mixing 25cm3 0.1m ch3cooh and 40cm3 0.1m ch3coo-na+. [ka = 1.74 x 10-5 m] ii. calculate the ph following the addition of a 10cm3 portion of 0.08 m naoh to 500cm3 of this buffer solution. iii. calculate the ph following the addition of a 10cm3 portion of 0.08 m hcl to 200cm3 of the original buffer solution.