How much heat is absorbed by 15.5 g of water when its temperature is increased from 20.0°c to 50.0°c? the specific heat of water is 4.184 j

The amount of heat that needs to be absorbed by a certain mass of water is calculated through the equation,
                            H = mcpdT
where m is mass, cp is specific heat, and dT is temperature difference.
                             H = (15.5 g)(4.184 J/g°C)(50°C - 20°C)
                               H = 1945.56 J
Thus, the amount of heat that needs to be absorbed is 1945.56 J.