What volume in ml of a 2.9m solution is needed in order to prepare 2.3l of a 1.1m solution?

tell me the equation too .

As i am reading the question, I notice they give two concentrations (M), one volume (L), and they are asking for another volume. this is a hint that you need to use the following formula

C1V1 = C2V2                (note: C stands for concentration)

C1= 2.9 M
V1= ?
C2= 1.1 M
V2= 2.3 L

now let's plug in the numbers

( 2.9 x V1)= (1.1 X 2.3)

V1= 0.87 Liters

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