What is the voltage of a battery that powers a light with .43 a and has a resistance of 3.5 ohms? a) 1.505 v eliminate b) 3.07 v c) 3.93 v d) 8.13 v

To determine the voltage of the battery above, we use Ohm's Law which relates voltage (V), current (I) and resistance (R) in a circuit. It is expressed as V = IR. We calculate as follows:

V = IR
V = .43 A ( 3.5 ohms )
V = 1.505 V

Therefore, the correct answer is option A.

Elias is almost correct. he just got it backwards.the correct answer is that it demonstrates elastic potential energy transforming into kinetic energy.

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