How many moles of o2 are needed to react with 1.44 mol of aluminum(al)?
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Aluminum reacts with oxygen based on the following equation:
 4Al + 3O2 → 2Al2O3

From this balanced equation, we can see that 4 moles of aluminum are required to react with 3 moles of oxygen.

So, to find the number of moles of oxygen needed to react with 1.44 moles of aluminum, all you have to do is cross multiplication as follows:
required moles of oxygen = (1.44x3) / 4 = 1.08 moles

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