What is the percent composition of carbon in glucose (c6h12o6)? (the molar mass of c = 12.01, h = 1.0079 and o = 16.00.)
3.36%
6.71%
15.20%
40%
53.29%

Answer : The correct option is, 40 %

Explanation: Given,

Molar mass of C = 12.01 g/mole

Molar mass of H = 1.0079 g/mole

Molar mass of O = 16.00 g/mole

First we have to calculate the molar mass of glucose.

Molar mass of glucose =

Now we have to calculate the percent composition of carbon in glucose.

As we now that there are 6 number of carbon atoms, 12 number of hydrogen atoms and 6 number of oxygen atoms.

The mass of carbon =

Formula used :

Now put all the given values in this formula, we get the percent composition of carbon in glucose.

Therefore, the percent composition of carbon in glucose is, 40 %

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c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current