In a given sample, hydrogen gas effuses four times faster than the other gas present in the mixture. what is the molar mass and identity of the unknown gas if the molar mass of hydrogen is 2 grams? 16 grams and oxygen 32 grams and oxygen 8 grams and nitrogen 4 grams and helium 64 grams and ozone

We need to use the effusion formula. I have attached a picture of what this formula looks like because it is a bit hard to type. 

effusion formula---> Rate 1/ rate 2= √(M2/M1)

as the questions states, hydrogen gas rate is 4 times the rate of the other gas. so, let call gas 1 the unknown and gas 2 the hydrogen

Rate 1= 1
Rate 2= 4

M1=??
M2= 2 grams

now let's plug in the values and solve for the unknown

1/4 = √(2/x)

x= 32 grams

with the choices given, the gases are either O₂, N₂ or O₃.

O₂ is the one whose mass is 32 because oxygen atomic mass in the periodic table is 16 grams. since we have two oxygens, then 16 x 2= 32

the answer is "32 grams and oxygen "

About 8 gallons of fuel will be used. (8.08)

The answer to the question: choose the correct statement.  a) when ethane reacts with fluorine gas the product is less stable.b) addition reactions of unsaturated hydrocarbons and halogens requires a high activation energy.  c)the double covalent bond within unsaturated hydrocarbons requires a lot of energy to break.  d)the double covalent bond within unsaturated hydrocarbons can be broken easily.is: a) when ethane reacts with fluorine gas the product is less stable.