What is the freezing point of a solution prepared by dissolving 50.0g of glycerin in 200g of ethanol?

-120 °C

Explanation:

The freezing point depression is calculated as follows:

ΔT = Kf*m

where ΔT is the difference between the freezing point of the pure solvent and from the solution; kf is a constant (equal to 2 °C/m for ethanol); and m is the molality of the solution.

moles of solute = (50 g)/(92.09 g/mol) = 0.54 mol

molality of the solution = moles of solute / kg of solvent

molality of the solution = 0.54 mol/ 0.2 kg = 2.7 m

ΔT = 2*2.7 = 5.4 °C

The freezing point of ethanol is -114.6 °C, then the freezing point of the solution is -114.6 °C - 5.4 °C =  -120 °C

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error