Consider the combustion reaction of acetylene (c2h2) : 2c2h2 + 5o2 mc001-1.jpg 4co2 + 2h2o use the periodic table to determine how many grams of oxygen would be required to react completely with 859.0 g c2h2?

2643.08g of O2

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Step 2:

Determination of the masses of C2H2 and O2 that reacted from the balanced equation. This is illustrated below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

Molar Mass of C2H2 = (12x2) + (2x1) = 24 + 2 = 26g/mol

Mass of C2H2 from the balanced equation = 2 x 26 = 52g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 5 x 32 = 160g

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Step 3:

Determination of the mass of oxygen that would be required to react completely with 859.0g of C2H2.

This is illustrated below:

From the balanced equation above,

52g of C2H2 reacted with 160g of O2.

Therefore, 859g of C2H2 will react with = (859 x 160)/52 = 2643.08g of O2.

From the calculations made above, 2643.08g of O2 will react completely with 895g of C2H2.

frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa