How many liters of methane gas (ch4) need to be combusted to produce 8.5 liters of water vapor, if all measurements are taken at the same temperature and pressure? show all of the work used to solve this problem. ch4 (g) + 2o2 (g) yields co2 (g) + 2h2o (g)

Answer : The volume of methane gas needed are 4.25 liters.

Explanation :

The balanced chemical reaction is:

At STP, 1 mole of substance contains 22.4 L volume of gas.

From the given reaction we conclude that,

1 mole of methane react to give 2 moles of water vapor.

As, volume of water vapor produced from 22.4 L volume of methane gas

So, 8.5 L volume of water vapor produced from volume of methane gas

Therefore, the volume of methane gas needed are 4.25 liters.

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