In an experiment, 0.42 mol of co and 0.42 mol of h2 were placed in a 1.00-l reaction vessel. at equilibrium, there were 0.29 mol of co remaining. keq at the temperature of the experiment is

To determine the Keq, we need the chemical reaction in the system. In this case it would be:

CO + 2H2 = CH3OH

The Keq is the ration of the amount of the product and the reactant. We use the ICE table for this. We do as follows:

          CO           H2             CH3OH
I         .42           .42                    0
C     -0.13      -2(0.13)            0.13

E =    .29           0.16               0.13

Therefore, 

Keq = [CH3OH] / [CO2] [H2]^2 = 0.13 / 0.29 (0.16^2)
Keq = 17.51

Afraidsugar lol it’s the third one