If the pressure of a 2.00 l sample of gas is 50.0 kpa, what pressure does the gas exert if its volume is decreased to 20.0 ml? what is the new pressure? kpa

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

P2 = P1V1/V2

P2 = 50 kPa x 2 L / .02 L

P2 = 5000 kPa

that's what i got you can count the number of atoms