Calculate the theoretical yield of iron(iii) oxide expected for this reaction if 0.50 mol of iron is reacted with excess oxygen
4fe + 3o2 yielding 2fe2o3
answer choices
.25 mol
.50 mol
.75 mol
1.0 mol

When you are dealing with mole calculations, whatever you do to one side of the equation you must also do to the other. .5Fe is 1/8th of 4Fe, so in order to determine what it will yield you must divide the given amount of Fe2O3 and divide THAT by 1/8th, leaving you with .25 mol of Fe2O3.