Chemistry, 01.09.2019 23:50 jkenkw4667

List 3 characteristics of chemical reactions and three characteristics of nuclear reactions

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Answer from: bnnn

explanation:

characteristics of chemical reactions are as follows.

chemical reactions leads to change in chemical composition of a substance. they can be exothermic or endothermic in nature. they can lead to formation of bubbles due to evolution of gas.

characteristics of nuclear reactions are as follows.

nuclear reaction leads to the formation of new isotopes and release of particles like neutrons, alpha or beta particles etc. both nuclear fission and fusion releases energy but nuclear fission releases more energy as compared to nuclear fusion. nuclear reactions changes the nucleus of an atom.

Answer from: Mrcastaway3036

The reaction in which composition of nucleus is altered through the release of energy and mass

Answer from: Quest

Ithink that’s it’s b

Answer from: Quest

Answerthis solution will not form a precipitateexplanationsolubility equilbrium: pbf₂(s) ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is $k_{sp} = [\text{pb}^{2+}][\text{f}^- ]^2 = 4 \times 10^{-8}$ (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as $q = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}}$ then, we can interpret q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product: $\begin{aligned} q & = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}} \\ & = (1.9 \times 10^{-3} ) (3.8\times 10^{3})^2 \\ & = 2.7 \times 10^{-8} \end{aligned}$ since q = 2.7 × 10⁻⁸ < ksp = 4 × 10⁻⁸, a precipitate will not form.

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List 3 characteristics of chemical reactions and three characteristics of nuclear reactions...