In the following combustion reaction of acetylene (c2h2), how many liters of co2 will be produced if 60 liters of o2 is used, given that both gases are at stp? 2c2h2+5o2 2h2o+4co2 the volume of one mole of gas at stp is 22.4 liters. 48 liters 0.02 liters 240 liters 300 liters nextreset

Answer : The volume of produced will be, 48 liters.

Explanation : Given,

Volume of = 60 L

First we have to calculate the moles of .

The given balanced chemical reaction is,

From the balanced chemical reaction, we conclude that

As, 22.4 L volume of present in 1 mole of

So, 60 L volume of present in mole of

Now we have to calculate the moles of .

From the reaction we conclude that,

As, 5 moles of react to give 4 moles of

So, 2.68 moles of react to give moles of

Now we have to calculate the volume of .

At STP,

As, 1 mole of contains 22.4 L volume of

So, 2.144 mole of contains volume of

Therefore, the volume of produced will be, 48 liters.

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