How many grams of iron metal do you expect to be produced when 265 grams of an 84.5 percent by mass iron (ii) nitrate solution reacts with excess aluminum metal? show all of the work needed to solve this problem.
2 al (s) + 3 fe(no3)2 (aq) 3 fe (s) + 2 al(no3)3 (aq)

the ratio of the conjugate base to the acid required to attain the desired ph.

answer: - first one is the correct answer. .

explanations: - potassium sulfide is and cobalt(ii) chloride is .

charge on k is +1, charge on s is -2, charge on co is +2 and charge on cl is -1.

in a double replacement reaction the ion exchange takes place. in general the reaction looks like:

if one of the product is insoluble as per solubility rules then a precipitate of it is formed.

when we mix the aqueous solutions of potassium sulfide and cobalt(ii) chloride then chloride ion goes with potassium ion and sulfide ion goes with cobalt ion and the balanced equation is written as:

k and cl has equal charges, similarly co and s has equal charges and hence no subscripts are used for the product side.

as per the solubility rules, cos is insoluble and so it's precipitate is formed.

looking at the given choices, first choice is correct.