Urgent
if 0.0010 mole of agno3 is added to 0.500 litres of a 0.00050 m solution of nabro3, will a precipitate of agbro3 form? justify your answer by showing your calculations. (ksp for agbro3 = 5.4 x 10-5)

There is 0.00025 moles of NaBrO₃ in the 0.5 L solution (0.5L×0.00050M=0.00025mol) which means that when 0.0010 moles of AgNO₃ is added only 0.00025 moles of AgBrO₃ can be made.  In other words, NaBrO₃ is the limiting reagent and since NaBrO₃ reacts with AgNO₃ in a 1 to 1 molar ratio, we know that only 0.00025 AgBrO₃ will be made before the amount of NaBrO₃ presant is used up.  I am assuming that the volume of the solution does not change while AgNO₃ is being added since the question does not state it which means that the concentration of AgBrO₃ is 0.0005M (0.00025mol÷0.5L=0.0005M)

To find out if AgBrO₃ precipitates out of solution you need to find the molar solubility of AgBrO₃ which is found by setting up the equation 5.4×10⁻⁵=[x][[x] and solving for x.  (this eqation basically the equation for Ksp but replacing the solute concentrations with the variable x).  When doing this you find that x=0.0073 mol/L which means that 0.0073 moles of AgBrO₃ can dissolve in 1 L of solution.  That means that 0.00367moles can dissolve in 0.5 L of solution.  

The first part of the question we found that we could produce 0.00025 moles of AgBrO₃ in the 0.5 L solution and in part two we found that 0.00367moles of AgBrO₃ in 0.5 L solution which means that no precipitate will form.

I hope this helps.  Let me know if anything is unclear or doesn't make sense.  I have not done a problem like this in a while so there could be some mistakes so I encourage you to check the work and see if it makes sense to you.

The answer should be c.

Contained in chromosomes which are located in the nucleus of the cell.