What mass of naoh is required to prepare 500.00 ml of 0.1300 m naoh stock solution, if the solid naoh is only 98.00% pure?

I would say it would depend on what the impurity is. But if the purity is determined as 98% pure by mass, then we can calculate:

Moles of NaOH in the stock solution:

Mass of pure NaOH solid () needed:

Mass of solid needed if 98% pure by mass:

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The answer is the first option just took the test