What is the approximate ph of a 0.06 m solution of ch3cooh (given that ka = 1.78 x 10-5)? 1 3 6 7 9

Answer : The pH of the solution is, 3

Solution :  Given,

Concentration (C) = 0.06 M

Acid dissociation constant =

The equilibrium reaction for dissociation of (weak acid) is,

initially conc.         c                                   0                  0

At eqm.                                                          

First we have to calculate the concentration of

As, we know that

   (for weak electrolyte)   ...........(1)

where, is degree of dissociation

      ..................(2)

By equation both the equations (1) and (2), we get

Now put all the given values in this expression, we get

Now we have to calculate the pH.

Therefore, the pH of the solution is, 3

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6