Consider the nuclear equation below.

what is the nuclide symbol of x?

a) 231/94 pu
b) 235/90 th
c) 239/94 pu
d) 231/90 th

Answer;

D) ²³¹₉₀Th

Explanation;

²³⁵₉₂U → ²³¹₉₀Th + ⁴₂He

This is known as alpha decay

Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and thereby transforms or 'decays' into a different atomic nucleus, with a mass number that is reduced by four and an atomic number that is reduced by two.

answermeridional ;