An electron in the n=6 level of the hydrogen atom relaxes to a lower energy level, emitting light of ? =93.8nm. find the principal level to which the electron relaxed.

We can find the principal level or lower level using Rydberg's formula:

1/w = R(1/L² - 1/U²) 

where:

w is the wavelength (93.8 nm),

L is the lower energy level (unknown)

U the upper energy level (n= 6)

R is Rydberg's constant (10,967,758 waves per meter)

Substituing known values into the equation:
1/(9.38 * 10^-8 m.) = 10,967,758(1/L² - 1-36)

Using the solver function of the calculator to get for L:

L = 0.999 
so L = 1. 
The lower level is 1 (the ground state).

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.