At stp, what is the volume of 4.50 moles of nitrogen gas

100.92 L

Explanation:

At STP,  

Pressure = 1 atm  

Temperature = 273.15 K

Given, moles = 4.50 moles

Volume = ?

Using ideal gas equation as:

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 4.50 moles × 0.0821 L.atm/K.mol × 273.15 K  

⇒V = 100.92 L

c. 75.7

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