The value of keq for the equilibrium h2 (g) + i2 (g) 2hi (g) is 794 at 25 °c. what is the value of keq for the equilibrium below? 1/2 h2 (g) + 1/2 i2 (g) hi (g)

The formula for Keq for the first chemical reaction with given Keq is:

Keq 1 = [ HI ]^2 /  [ H2 ] [ I2 ]

While the formula for Keq for the 2nd is:

Keq 2 = [ HI ] /  [ H2 ]^(1/2) [ I2 ]^(1/2)

We can see that the coefficients in the reaction are equal to the exponents in the equilibrium equation. Therefore if we divide the whole reaction by 2, then that means we have to take the square root of the equilibrium equation. Or in this case,

Keq 2 = sqrt (Keq 1)

Keq 2 = sqrt (794)

Keq 2 = 28.19

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.

i don,t know so just answer mine