Chemistry, 06.01.2020 03:31 breonnabyers

Acompany desires to produce nickel from refining nickel oxide and sulfide ores. the first step of the process will produce a nickel carbonyl gas ni(co)4 by heating the ore. the second step is as follows: ni(co)4(g) ni(s) + 4co(g) how would you accelerate the production of ni?
select all that apply.

reduce the concentration of nico4
increase the concentration of nico4
withdraw co from the products as it is forming
adding co to the reaction

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Answer from: batmanmarie2004

increase the concentration of NiCO4

withdraw CO from the products as it is forming

Explanation:

According to Le Chatelier's principle when a system at equilibrium is subjected to changes in temperature, pressure or concentration the equilibrium will shift in a direction to undo the effect of the induced change.

The given reaction is:

$Ni(CO)4(g)\rightleftharpoons Ni(s) + 4CO(g)$

In order to increase the amount of Ni, two approaches can be adopted

1) Increasing the concentration of Ni(CO)4 will shift the equilibrium in a direction that would enhance its consumption i.e. towards the right

2) Withdrawing CO from the reaction will shift the equilibrium in a direction that would increase its production i.e. to the right

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

a is the answer to this question

explanation:

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