Asolution is prepared by dissolving 16.2 g of benzene (c6h6) in 282 g of carbon tetrachloride (ccl4). the concentration of benzene in this solution is molal. the molar masses of c6h6 and ccl4 are 78.1 g/mol and 154 g/mol, respectively.

Molality is one way of expressing concentration of a substance in a solution. It is moles of the substance per kilogram of the solvent in the solution. So, in order, to determine the molality of the solute benzene in the solution given above, we need to know the moles of benzene and the kilograms of the solvent carbon tetrachloride. We calculate as follows:

Molality = moles benzene / mass of carbon tetrachloride
Molality = 16.2 g benzene ( 1 mol / 78.1 g ) / 282 g CCl4 ( 1 kg / 1000 g)
Molality = 0.7356 mol C6H6 / kg CCl4 or 0.7356 molal

Therefore, the concentration of benzene in this solution is 0.7356 molal.

Hi + naoh -> h2o + nal