What net ionic equation can be derived from this complete ionic equation? 2fe3+(aq) + 6cl– (aq) + 6na+(aq) + 3co32– (aq) → fe2(co3)3(s) + 6cl– (aq) + 6na+(aq)?

So, in order to get the net ionic equation, we consider only the ions that reacted in the total ionic equation. We use these ions to get the net ionic equation.

Examining the total ionic equation provided, we will find that the only ions that reacted are the 2fe3+(aq) and the 3co32– (aq) ions which reacted together forming fe2(co3)3(s).

Based on this, the net ionic equation will be:
2Fe3+ (aq) + 3CO32- (aq) > Fe2(CO3)3 (s) 

In any atom of any element, you will find protons and neutrons in the nucleus of any atom 

  the volume of  0.220 m k2s    solution  required  to  completely  react with 175 ml  of 0.115m co(no3)2  calculate the moles  of co(no3)2 =  molarity x volume/1000175 x0.115/1000= 0.02  moleswrite  the reacting  equationk2s(aq)  +  co(no3)2  = 2 kno3(aq)  + cos(s)by  use  of mole ratio between k2s to co(no3)2 which  is  1: 1 the moles of k2s is therefore = 175  x0.115/1000= 0.02  molesvolume = moles/molarity=0.02/0.22=0.09  ml  of k2s