Roger pushes a box on a 30° incline. if he applies a force of 60 newtons parallel to the incline and displaces the box 10 meters along the incline, how much work will he do on the box?

5.2x10^2 joules
6.0x10^2 joules
-5.2x10^2 joules
-6.0x10^2 joules

Hi. This is not a chemistry question but a physics one.

Work = force * parallel distance

You do not have to use trigonometry to calculate any value in this problem, because the force applied and the displacement given are parallel.

=> Work = 60 N * 10m = 600 joules = 6.0 * 10^2 joules.

6.0 * 10^2 joules

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