Which k values would indicate that there is more b than a at equilibrium?
a)k=2×10^5 b)k=.4 c)k=8000 d)6×10^-7

Assuming that the reaction is the following:

A -> B
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The k expression would be written as the concentration or amount of product divided by the amount of reactant. In the case, where the quantity of B is much larger than A would result in a very small K value, which in this case would be D. 6 X 10^-7.

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !