If a cell is isotonic with a 0.88% nacl solution, how would an extracellular fluid with 1% nacl affect the cell?

The cell will shrink when kept in 1% NaCl solution.

Explanation: This is explained with the help of osmosis.

Osmosis is a process in which the solvent flow from a solution of low concentration to a solution of high concentration through a semi-permeable membrane.

We a given a cell which is isotonic to 0.88% NaCl solution.

When the same cell is kept in a solution of 1% NaCl solution, osmosis will occur from inside to outside because the concentration is low inside the cell than the outside. So, the solvent will flow from inside to outside, which results in the shrinkage of cell. The solutions which have high concentration outside the cell are known as hypertonic solutions.

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

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(jacemorris04)