Curious carl and his lab partner need 100 ml of a 0.10 m cuso4 solution for lab. unfortunately, all they have is 1 liter of a 0.50 m cuso4 stock solution. cheryl, his lab partner knows what to do. she begins diluting the stock solution with distilled water. how much 0.50 m stock solution is required to make 100 ml of a 0.10 m solution? a) 5.0 ml b) 10.0 ml c) 20.0 ml d) 50.0 ml

This problem is common especially when preparing solutions from stock solution. To solve this, we make use of the dilution formula: C1V1 = C2V2, where,

C1 and C2 are the concentration of solutions 1 and 2, respectively
V1 and V2 are the volume of solutions 1 and 2, respectively

In this case, the resulting equation to determine the amount of 0.50 M stock solution of CuSO4 needed is:
(0.50 M CuSO4)(Volume of 0.50 M stock solution) = (0.10 M CuSO4) (100 mL)

Thus, the final answer is C. 20 mL of 0.50 M stock solution is required to make 100 ml of a 0.10 M CuSO4 solution. 

The use of piers and beams to build a strong foundation for a house.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na