How many zn atoms are contained in 922 g of zn

There are two conversions that we need to do here. First, we convert the mass into moles through the use of molar mass. Second, we convert the number of moles to number of atoms through the use of the Avogadro's number.

With the use of the periodic table, we know that the molar mass of zinc is 65.38 grams per mole. This is obtained as the average atomic mass of all the naturally occurring isotopes of Zinc. So, we divide he mass of zinc with its molar mass:

Moles of zinc = 922 g / 65.28 g/mol = 14.124 moles

Next, we use the Avogadro's number. For every 1 mole of any substance, there is a corresponding amount of 6.022×10²³ particles. These particles could refer to atoms, molecules or any sub-atomic particles. So, the next conversion would be:

14.124 moles * 6.022×10²³ particles/mole = 8.506×10²⁴ particles

Therefore, there are a total of 8.506×10²⁴ atoms in 922 grams of Zinc.

The answer will be c