What volume of nitrous oxide (n20) can be produced from the decomposition of 0.55 moles of ammonium nitrate (nh4no3). nh4no3 (s) àn2o (g) + 2h2o (g)

1 mol of gas at STP ⇒22,4dm³

1 mol22,4dm³
NH₄NO₃(s) > N₂O(g) + 2H₂O(g)
0,55 mol X

X = (0,55×22,4)/1
X = 12,32 dm³ N₂O

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Ethene molecular fórmula= c2h4molecular weight = 29.046g/molhope it : )