For a 0.50 molal solution of sucrose in water, calculate the freezing point and the boiling point of the solution. list each step.

We can solve for the freezing point and the boiling point of the solutions by using the freezing point depression and boiling point elevation formulas.

ΔTb = Kb m i

ΔTf = Kf m i

where,

Kb and Kf are the boiling point and freezing point constants for water

Kb = 0.51 °C / molal

Kf = - 1.86 °C / molal

m = molality = 0.50 molal

i = vant Hoff factor = 1

The freezing point and boiling points are:

Freezing point = 0°C + ΔTf

Freezing point = 0°C + (-1.86 °C / molal * 0.5 molal)

Freezing point = - 0.93 °C

Boiling point = 100°C + ΔTb

Boiling point = 100°C + (0.51 °C / molal * 0.5 molal)

Boiling point = 100.255°C

mark him as !